Vereinfache:
Schreibe als Bruch und vereinfache das Ergebnis:
23+56=46+56=96=32‾\frac{2}{3} + \frac{5}{6} = \frac{4}{6}+\frac{5}{6}=\frac{9}{6}=\underline{\frac{3}{2}}
34−13=912−412=512‾\frac{3}{4} - \frac{1}{3}=\frac{9}{12}-\frac{4}{12}=\underline{\frac{5}{12}}
74+85−110=3520+3220−220=6520=134‾\frac{7}{4} + \frac{8}{5} - \frac{1}{10}=\frac{35}{20}+\frac{32}{20}-\frac{2}{20}=\frac{65}{20}=\underline{\frac{13}{4}}
5b4+3b4=8b4=2b‾\frac{5b}{4} + \frac{3b}{4}=\frac{8b}{4}=\underline{2b}
3x2b−x2b=2x2b=xb‾\frac{3x}{2b} - \frac{x}{2b}=\frac{2x}{2b}=\underline{\frac{x}{b}}
6aa−b−15ba−b+9aa−b=6a−15b+9aa−b=15a−15ba−b=15(a−b)a−b=15‾\frac{6a}{a-b} - \frac{15b}{a-b} +\frac{9a}{a-b}=\frac{6a-15b+9a}{a-b}=\frac{15a-15b}{a-b} = \frac{15(a-b)}{a-b}=\underline{15}
10a[3b−2(3a−2b)]a(m−n)−5a[2b+3(2a−3b)]a(m−n)=10[3b−2(3a−2b)]m−n−5[2b+3(2a−3b)]m−n=10[3b−2(3a−2b)]−5[2b+3(2a−3b)]m−n=5⋅2[3b−2(3a−2b)]−[2b+3(2a−3b)]m−n=5⋅6b−4(3a−2b)−2b−3(2a−3b)m−n=5⋅6b−12a+8b−2b−6a+9bm−n=5⋅21b−18am−n=5⋅3(7b−6a)m−n=15(7b−6a)m−n‾\frac{10a[3b-2(3a-2b)]}{a(m-n)} - \frac{5a[2b+3(2a-3b)]}{a(m-n)}\\=\frac{10[3b-2(3a-2b)]}{m-n}-\frac{5[2b+3(2a-3b)]}{m-n}\\= \frac{10[3b-2(3a-2b)]-5[2b+3(2a-3b)]}{m-n}\\=5\cdot\frac{2[3b-2(3a-2b)]-[2b+3(2a-3b)]}{m-n} \\= 5\cdot\frac{6b-4(3a-2b)-2b-3(2a-3b)}{m-n}\\=5\cdot\frac{6b-12a+8b-2b-6a+9b}{m-n} \\= 5\cdot\frac{21b-18a}{m-n}\\=5\cdot\frac{3(7b-6a)}{m-n}=\underline{\frac{15(7b-6a)}{m-n}}
3a−4b4+a+6b3−7a+b6=3(3a−4b)12+4(a+6b)12−2(7a+b)12=9a−12b+4a+24b−14a−2b12=10b−a12‾\frac{3a-4b}{4}+\frac{a+6b}{3}-\frac{7a+b}{6}\\=\frac{3(3a-4b)}{12}+\frac{4(a+6b)}{12}-\frac{2(7a+b)}{12}\\=\frac{9a-12b+4a+24b-14a-2b}{12}\\=\underline{\frac{10b-a}{12}}
2m15ab−3n5a=2m15ab−9bn15ab=2m−9bn15ab‾\frac{2m}{15ab}-\frac{3n}{5a}=\frac{2m}{15ab}-\frac{9bn}{15ab}=\underline{\frac{2m-9bn}{15ab}}
5y−4x18y−3x+2y4xy=2x(5y−4x)36xy−9(3x+2y)36xy=10xy−8x2−27x−18y36xy‾\frac{5y-4x}{18y}-\frac{3x+2y}{4xy}=\frac{2x(5y-4x)}{36xy}-\frac{9(3x+2y)}{36xy}=\underline{\frac{10xy-8x^2-27x-18y}{36xy}}
2v9ab−3u2ac+5w6abc=2c⋅2v18abc−9b⋅3u18abc+3⋅5w18abc=4cv−27bu+15w18abc‾\frac{2v}{9ab} - \frac{3u}{2ac} + \frac{5w}{6abc}= \frac{2c \cdot 2v}{18abc} - \frac{9b \cdot 3u}{18abc} + \frac{3 \cdot 5w}{18abc}= \underline{\frac{4cv - 27bu + 15w}{18abc}}
1−2x−3y2x=2x2x−2x−3y2x=2x−(2x−3y)2x=2x−2x+3y2x=3y2x‾1-\frac{2x-3y}{2x}=\frac{2x}{2x}-\frac{2x-3y}{2x}=\frac{2x-(2x-3y)}{2x}=\frac{2x-2x+3y}{2x}=\underline{\frac{3y}{2x}}or: …=1−(2x2x−3y2x)=1−1+3y2x=3y2x‾\quad \ldots = 1-\left(\frac{2x}{2x}-\frac{3y}{2x}\right)=1-1+\frac{3y}{2x}=\underline{\frac{3y}{2x}}
5x+730ab+2−9x15bc+6x−1512ac=2c(5x+7)60abc+4a(2−9x)60abc+5b(6x−15)60abc=10cx+14c+8a−36ax+30bx−75b60abc‾\frac{5x+7}{30ab} + \frac{2-9x}{15bc} + \frac{6x-15}{12ac}= \frac{2c(5x+7)}{60abc} + \frac{4a(2-9x)}{60abc} + \frac{5b(6x-15)}{60abc}\\= \underline{\frac{10cx+14c+8a-36ax+30bx-75b}{60abc}}
4x+4y6a−2−x+3y3a−1+4y9a−3=4x+4y2(3a−1)−x+3y3a−1+4y3(3a−1)=3(4x+4y)6(3a−1)−6(x+3y)6(3a−1)+2⋅4y6(3a−1)=12x+12y−6x−18y+8y6(3a−1)=6x+2y6(3a−1)=3x+y3(3a−1)‾\frac{4x+4y}{6a-2} - \frac{x+3y}{3a-1} + \frac{4y}{9a-3}= \frac{4x+4y}{2(3a-1)} - \frac{x+3y}{3a-1} + \frac{4y}{3(3a-1)}\\=\frac{3(4x+4y)}{6(3a-1)} - \frac{6(x+3y)}{6(3a-1)} + \frac{2 \cdot 4y}{6(3a-1)}\\ = \frac{12x+12y-6x-18y+8y}{6(3a-1)}\\=\frac{6x+2y}{6(3a-1)}\\= \underline{\frac{3x+y}{3(3a-1)}}
2x+y8x−4y+2x−y6x+3y−3xy4x2−y2=2x+y4(2x−y)+2x−y3(x+2y)−3xy(2x+y)(2x−y)=3(2x+y)212(2x+y)(2x−y)+4(2x−y)212(2x+y)(2x−y)−12⋅3xy12(2x+y)(2x−y)=3(4x2+4xy+y2)+4(4x2−4xy+y2)−36xy12(2x+y)(2x−y)=12x2+12xy+3y2+16x2−16xy+4y2−36xy12(2x+y)(2x−y)=28x2−40xy+7y212(4x2−y2)‾\frac{2x+y}{8x-4y}+\frac{2x-y}{6x+3y}-\frac{3xy}{4x^2-y^2}\\=\frac{2x+y}{4(2x-y)} + \frac{2x-y}{3(x+2y)}-\frac{3xy}{(2x+y)(2x-y)} \\=\frac{3(2x+y)^2}{12(2x+y)(2x-y)} + \frac{4(2x-y)^2}{12(2x+y)(2x-y)} - \frac{12 \cdot 3xy}{12(2x+y)(2x-y)} \\= \frac{3(4x^2+4xy+y^2)+4(4x^2-4xy+y^2)-36xy}{12(2x+y)(2x-y)} \\= \frac{12x^2+12xy+3y^2+16x^2-16xy+4y^2-36xy}{12(2x+y)(2x-y)}=\underline{\frac{28x^2-40xy+7y^2}{12(4x^2-y^2)}}
(3x−2)24−9x2+27x2−1227x2−36x+12=(3x−2)24−9x2+3(9x2−4)3(9x2−12x+4)=(3x−2)2(2+3x)(2−3x)+3(3x+2)(3x−2)3(3x−2)2=(3x−2)2−(3x+2)(3x−2)+3x+23x−2=−(3x−2)2(3x+2)(3x−2)+(3x+2)2(3x+2)(3x−2)=−(9x2−12x+4)+(9x2+12x+4)(3x+2)(3x−2)=24x9x2−4‾\frac{(3x-2)^2}{4-9x^2}+\frac{27x^2-12}{27x^2-36x+12}=\frac{(3x-2)^2}{4-9x^2} + \frac{3(9x^2-4)}{3(9x^2-12x+4)}\\=\frac{(3x-2)^2}{(2+3x)(2-3x)} + \frac{3(3x+2)(3x-2)}{3(3x-2)^2}\\ = \frac{(3x-2)^2}{-(3x+2)(3x-2)} + \frac{3x+2}{3x-2} \\= -\frac{(3x-2)^2}{(3x+2)(3x-2)} + \frac{(3x+2)^2}{(3x+2)(3x-2)} \\=\frac{-(9x^2-12x+4)+(9x^2+12x+4)}{(3x+2)(3x-2)} = \underline{\frac{24x}{9x^2-4}}
7a−2a21−4a2+a+12a−1−2a2a+1=7a−2a2(1−2a)(1+2a)+a+12a−1−2a2a+1=7a−2a2−(2a−1)(2a+1)+(a+1)(2a+1)(2a−1)(2a+1)−(2a−1)2a(2a−1)(2a+1)=−(7a−2a2)+2a2+a+2a+1−(4a2−2a)(2a−1)(2a+1)=−7a+2a2+2a2+3a+1−4a2+2a(2a−1)(2a+1)=1−2a−(1−2a)(2a+1)=−12a+1‾\frac{7a-2a^2}{1-4a^2} + \frac{a+1}{2a-1} - \frac{2a}{2a+1}=\frac{7a-2a^2}{(1-2a)(1+2a)} + \frac{a+1}{2a-1} - \frac{2a}{2a+1}\\= \frac{7a-2a^2}{-(2a-1)(2a+1)} + \frac{(a+1)(2a+1)}{(2a-1)(2a+1)} - \frac{(2a-1)2a}{(2a-1)(2a+1)} \\= \frac{-(7a-2a^2)+2a^2+a+2a+1-(4a^2-2a)}{(2a-1)(2a+1)} \\= \frac{-7a+2a^2+2a^2+3a+1-4a^2+2a}{(2a-1)(2a+1)} \\= \frac{1-2a}{-(1-2a)(2a+1)}\\=\underline{-\frac{1}{2a+1}}