Some geometrical facts

Let's summarize some of the geometrical properties we have observed in the last section. Let's start with parallel and orthogonal straight lines:

Theorem 1

Consider two straight lines gg and hh with slope aa and bb.

  1. gg and gg are parallel, if they have the same slope: gh    a=bg \parallel h \iff a=b
  2. Two lines are orthogonal (that is, they for a right angle), if the product of the two slopes is 1-1: gh    ab=1g \perp h \iff ab=-1 (instead of the condition ab=1ab=-1 can we also use a=1ba=-\frac{1}{b} or b=1ab=-\frac{1}{a}).
Exercise 1

Consider two linear function ff and gg. Are they parallel, orthogonal, or neither?

  1. f(x)=3x+2f(x)=-3x+2 and g(x)=63xg(x)=6-3x

  2. f(x)=10x+1f(x)=10x+1 and g(x)=0.1x1g(x)=-0.1x-1

  3. f(x)=4x+3f(x)=4x+3 and g(x)=0.25x+1g(x)=0.25x+1

Solution
  1. parallel, because same slope 3-3
  2. orthogonal, because 10(0.1)=110\cdot (-0.1)= -1
  3. neither, because the have not the same slope, and their product is not 1-1.

We also have looked at the intercept theorem, which comes in handy from time to time. Let us state it here in more detail:

Theorem 2: Intercept theorem

Consider two lines that intersect at point PP, and two lines gg and hh that traverse these two lines, resulting in the intersection points AA, BB, AA^\prime and BB^\prime (see figure below). The following is then true:

gh    PAPA=PBPB=ABABg \parallel h \iff \frac{PA^\prime}{PA}=\frac{PB^\prime}{PB}=\frac{A^\prime B^\prime}{AB}

Here, with ABAB we mean the distance between AA and BB, and so on.

Exercise 2

Use the intercept theorem to determine the length xx in the figure below.

Solution

104=3+x37.5=3+xx=4.5\frac{10}{4}=\frac{3+x}{3}\rightarrow 7.5=3+x\rightarrow x=\underline{4.5}.